Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Mike draws a triangle and dilates it by a scale factor of 2.5. If the triangle's original dimensions are 4 inches high and 6 in...Question
Mike draws a triangle and dilates it by a scale factor of 2.5. If the triangle's original dimensions are 4 inches high and 6 inches along its base, what is the area in square inches of Mike's dilated triangle?
A. 24
B. 75
C. 150
D. 60
A. 24
B. 75
C. 150
D. 60
Answers
Answered by
GPT-4o mini
To find the area of the dilated triangle, we first need to determine the area of the original triangle using the formula for the area of a triangle:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
For the original triangle, the height is 4 inches, and the base is 6 inches. Plugging these values into the formula gives:
\[
\text{Area} = \frac{1}{2} \times 6 \times 4 = \frac{1}{2} \times 24 = 12 \text{ square inches}
\]
Next, when we dilate the triangle by a scale factor of 2.5, the dimensions of the triangle will be multiplied by this scale factor. Specifically:
- The new height will be: \( 4 \times 2.5 = 10 \) inches
- The new base will be: \( 6 \times 2.5 = 15 \) inches
Now we can find the area of the dilated triangle using the same area formula:
\[
\text{Area} = \frac{1}{2} \times 15 \times 10 = \frac{1}{2} \times 150 = 75 \text{ square inches}
\]
Thus, the area of Mike's dilated triangle is \( \boxed{75} \).
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
For the original triangle, the height is 4 inches, and the base is 6 inches. Plugging these values into the formula gives:
\[
\text{Area} = \frac{1}{2} \times 6 \times 4 = \frac{1}{2} \times 24 = 12 \text{ square inches}
\]
Next, when we dilate the triangle by a scale factor of 2.5, the dimensions of the triangle will be multiplied by this scale factor. Specifically:
- The new height will be: \( 4 \times 2.5 = 10 \) inches
- The new base will be: \( 6 \times 2.5 = 15 \) inches
Now we can find the area of the dilated triangle using the same area formula:
\[
\text{Area} = \frac{1}{2} \times 15 \times 10 = \frac{1}{2} \times 150 = 75 \text{ square inches}
\]
Thus, the area of Mike's dilated triangle is \( \boxed{75} \).
There are no human answers yet. A form for humans to post answers is coming very soon!