Mike draws a triangle and dilates it by a scale factor of 2.5. If the triangle’s original dimensions are 4 inches high and 6 inches along its base, what is the area in square inches of Mike’s dilated triangle? (1 point) Responses 60 60 24 24 75 75 150

1 answer

To find the area of Mike's dilated triangle, we can start by calculating the area of the original triangle and then apply the effects of the dilation.

The formula for the area \(A\) of a triangle is:

\[ A = \frac{1}{2} \times \text{base} \times \text{height} \]

For the original triangle:

  • Base = 6 inches
  • Height = 4 inches

Calculating the area of the original triangle:

\[ A_{\text{original}} = \frac{1}{2} \times 6 \times 4 = \frac{1}{2} \times 24 = 12 \text{ square inches} \]

When a shape is dilated by a scale factor \(k\), the area of the new shape is scaled by a factor of \(k^2\). In this case, the scale factor is 2.5:

\[ k = 2.5 \]

Calculating the area of the dilated triangle:

\[ A_{\text{dilated}} = A_{\text{original}} \times k^2 = 12 \times (2.5)^2 \]

Now calculating \( (2.5)^2 \):

\[ (2.5)^2 = 6.25 \]

Now calculating the area of the dilated triangle:

\[ A_{\text{dilated}} = 12 \times 6.25 = 75 \text{ square inches} \]

Thus, the area of Mike's dilated triangle is \( \boxed{75} \) square inches.