mike claims that the probability of winning a pick 6 number game where six numbers are drawn from the set 1 through 49 is about the same as getting 24 heads in a row when you flip a fair coin

1. find the probability of winning the pick 6 game and the probability of getting 24 heads in a row when you flip a fair coin.

i do not get this?!

1 answer

prob of winning 6/49
= 1/(C(49,6)) = 1/13983816 = .000000071

prob of throwing 24 heads in a row
= (1/2)^24 = 1/16777216 = .000000059