Let \( x \) be the number of pounds of Type A coffee. Since Miguel used three times as many pounds of Type B coffee as Type A, the amount of Type B coffee used would be \( 3x \) pounds.
Now we can set up an equation for the total cost of the coffee blend based on the given costs:
- The cost of Type A coffee is \( 5.95x \).
- The cost of Type B coffee is \( 4.65(3x) = 13.95x \).
The total cost of the blend is the sum of the costs of Type A and Type B:
\[ 5.95x + 13.95x = 796 \]
Combining the terms on the left:
\[ 19.90x = 796 \]
Now, we solve for \( x \):
\[ x = \frac{796}{19.90} \approx 40 \]
Therefore, the number of pounds of Type A coffee used is \( 40 \).
So, the answer is:
\[ \boxed{40} \]