First, let's calculate the volume of the paint bucket using the formula for the volume of a cylinder:
V = πr^2h
Where:
V = volume
π = 3.14
r = radius = 5.9 inches
h = height = 15.6 inches
Substitute the values into the formula:
V = 3.14 * (5.9)^2 * 15.6
V = 3.14 * 34.81 * 15.6
V = 3.14 * 543.936
V = 1707.55424
Rounded to the nearest tenth, the volume of the paint bucket is approximately 1707.6 cubic inches.
Michelle just bought a 5-gallon paint can. The paint bucket resembles a right circular cylinder. If the height is 15.6 inches, and the radius is 5.9 inches, what is the volume of the paint bucket? Use 3.14 for π. Round to the nearest tenth.(1 point
3 answers
Wrong
My apologies for the mistake. Let's correct it.
Given:
Height (h) = 15.6 inches
Radius (r) = 5.9 inches
Pi (π) = 3.14
We will use the formula for the volume of a cylinder:
V = πr^2h
Substitute the values into the formula:
V = 3.14 * (5.9)^2 * 15.6
V = 3.14 * 34.81 * 15.6
V = 3.14 * 543.336
V = 1705.00224
Rounded to the nearest tenth, the volume of the paint bucket is approximately 1705.0 cubic inches.
Given:
Height (h) = 15.6 inches
Radius (r) = 5.9 inches
Pi (π) = 3.14
We will use the formula for the volume of a cylinder:
V = πr^2h
Substitute the values into the formula:
V = 3.14 * (5.9)^2 * 15.6
V = 3.14 * 34.81 * 15.6
V = 3.14 * 543.336
V = 1705.00224
Rounded to the nearest tenth, the volume of the paint bucket is approximately 1705.0 cubic inches.
1 answer