well... from what I understand, the reason that the product separates from the NaOH is because the product is dissolvable in acetone while the inorganic by-products and such are not. Thus after centrifuging the mixture, all the supernatant (acetone) has the product.
I got 1.43g as percent yield
Michael & Aldol Condensation Reaction
We are preparing an a,b-unsaturated ketone via Michael and aldol condensation reactions. The reactants are trans-chalcone and ethyl acetoacetate (in ethanol and NaOH). This creates 6-ethoxycarbonyl-3,5-diphenyl-2-cyclohexenone. What I'm wondering is:
Why is it possible to separate the product from sodium hydroxide using acetone?
Could you tell me what is the purpose of this reaction (Michael and aldol condensation reactions), and the stepwise mechanism of the reaction.
Also if we started with 1.2 grams of trans-chalcone , 0.75 grams of ethyl acetoacetate what would be the theoretical yield ?
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