'm'gms of carbon reacts completely with 'n'gms of oxygen to produce carbon-dioxide.The mass of oxygen required to react with 'm'gms of carbon completely and produce carbon-monoxide is

Answer 1

Not entirely sure what is needed here

Start from the equations

C + O2 -> CO2

1 mole + 1 mole -> 1 mole

so

m/12 + n/32 produces CO2

so m/12=n/32 or

32m=12n

8m=3n

n=8m/3

C + 1/2O2 -> CO

1 mole + 1/2 mole -> 1 mole

m/12 n/32

in this case

m/12= 2n/32

m/12=n/16

mass of O2 required is

16m/12 or 4m/3

which is what we expect as half the number of moles i.e. half the mass i needed.