I have corrected your equation.
Mg3N2 + 6H20 = 3Mg(OH)2 + 2NH3
How many mols NH3 are in 25 g? That's mols = grams/molar mass = 25/17 = estimated 1.5 but you need to use a more accurate number.
Convert mols NH3 to mols Mg3N2 using the coefficients in the balance equation.
1.5 mols NH3 x (1 mol Mg3N2/2 mol NH3) = estimated 0.75 Mg3N2. Now convert that to grams. g = mols Mg3N2 x molar mass Mg3N2
Post your work if you get stuck.
Mg3N2 + 6H20 = 3Mg(OH) + 2NH3
What mass of magnesium nitride would you need to react with excess water to produce 25g of ammonia?
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