methylamine is a weak base. calculate the pH of a .025 M solution of methylamine.

Answer 1

..........CH3NH2 + HOH --> CH3NH3^+ + OH^-
I..........0.025............0..........0
C...........-x..............x..........x
E........0.025-x............x..........x

You need the Kb for CH3NH2. You can find that in your text/notes/web.

Substitute the E line into Kb expression and solve for x = (OH^-) and convert that to pH. You may need to solve for quadratic depending upon how close your prof wants the answer.