.........A ==> 2B
I....0.154.....0
C........-x....2x
E...0.154-x....2x
Substitute the E line into Kc expression and solve for x and 0.154-x.
I don't know if the prof expects you to answer this with math (working out the above equation) or by reason but the math should do it but take more time. I suspect the answer is c but I didn't go through the math. None of the others can be right so c is elected by elimination of the others.
Method for getting correct answer for this? Thank you!
For the reaction A ↔ 2B K = 3.80x10-7 , if one started with 0.154 M A approximately how much A and B would there be after equilibrium had been established?
a. very little A, 0.154 M B
b. 0.126 M A; 0.027 M B
c. 0.154 M A, very little B
d. 0.027 M A; 0.126 M B
1 answer