Method for getting correct answer for this? Thank you! A mixture containing an initial concentration of 0.1877 M for H2 and 0.1432 M for Cl2 is allowed to come to equilibrium (see reaction below). What must be the equilibrium concentration of HCl?

H2(g) + Cl2(g) ↔ 2HCl(g) Kc = 5.00e16

a. 0.1432 M

b. 0.0716 M

c. 0.2864 M

d. 0.0865 M

1 answer

........H2 + Cl2 ==> 2HCl
I...0.1877.0.1432......0
C.......-x....-x.......2x
E...0.1877-x.0.1432-x..2x

Substitute the E line into Kc expression and solve for x, then evaluate each individual term.