66 g
72.8%
Methanol(CH4O),used in racing cars,burns O2 to form CO2and H2O.
2CH4O(l) + 3O2(g)-->2Co2(g) +4H2O(g)
32.0g/mol 32.g/mol 44.g/mol 18.g/mol
What is the theoretical yield of CO2 from 48 g of methanol?
What is the percent yield of CO2 if 48.0g og CO2 are formed?
1 answer