Methanol (CH3OH) can be made by controlled oxidation of methane.
CH4(g) + 1/2 O2(g) �¨ CH3OH(g)
I found that the
ƒ¢H�‹ is -126.4kJ/K and the ƒ¢S�‹ is -51.2, and the ƒ¢G�‹ at 298 K is 111kJ
Yet how do you
Calculate the temperature at equilibrium? please show steps if possible
1 answer
It will be delta H over delta S because at equilibrium delta G is equal to 0
1 answer