Methane burns in the presence of oxygen to create carbon dioxide and water explain in detail the steps you would need to take To write a balanced equation for the chemical reaction you need four steps
3 answers
oobleck and I have done three of these stoichiometry problems for you. I'll be glad to check your work if you will post it.
Thank you. I’m working on it now. I’m really struggling in this unit.
Steps to solve stoichiometry problems. This will do them all.
1. Write and balance the equation.
2. Convert what you have to moles. For solids it is mols = grams/molar mass. For solution it is moles = molarity x liters.
3. Using the coefficients in the balanced equation (from step 1), convert moles of what you have to moles of what you want.
4. Depends upon the question. If you want moles you have that and you're done. If you want grams of the product/reactant then g = mols x molar mass. If you want concentration it is M = moles/L of solution.
Look at the earlier SO2/CO problem.
1. You were given the balanced equation.
2. You converted what you had (17 g CO) to moles. moles CO = 17/28.01 = 0.606 mols CO.
3. Convert mols of what you have (0.606 mols CO) to moles of what you want (moles SO2). 0.606 x ((2 mols SO2/4 moles CO) = 0.303 moles SO2.
4. You're done. If the problem asked for grams SO2, then mols SO2 x molar mass SO2 = 0.303 x 64 g SO2/mole SO2) = about 19 g SO2.
Hope this helps. Don't let chemistry get you down.
1. Write and balance the equation.
2. Convert what you have to moles. For solids it is mols = grams/molar mass. For solution it is moles = molarity x liters.
3. Using the coefficients in the balanced equation (from step 1), convert moles of what you have to moles of what you want.
4. Depends upon the question. If you want moles you have that and you're done. If you want grams of the product/reactant then g = mols x molar mass. If you want concentration it is M = moles/L of solution.
Look at the earlier SO2/CO problem.
1. You were given the balanced equation.
2. You converted what you had (17 g CO) to moles. moles CO = 17/28.01 = 0.606 mols CO.
3. Convert mols of what you have (0.606 mols CO) to moles of what you want (moles SO2). 0.606 x ((2 mols SO2/4 moles CO) = 0.303 moles SO2.
4. You're done. If the problem asked for grams SO2, then mols SO2 x molar mass SO2 = 0.303 x 64 g SO2/mole SO2) = about 19 g SO2.
Hope this helps. Don't let chemistry get you down.