Mendel studied seven characters in pea plants and found that they all followed the laws of segregation and independent assortment. For example, the gene for flower color and the gene for flower position are located on different chromosomes.

Question

The flower color gene has two alleles: P (purple) and p (white).
The flower position gene has two alleles: A (axial) and a (terminal).
Which of the following genotypes could be produced in gametes from a plant with genotype AAPp? Select all that apply.

Pp
AA
AP
ap
Ap

Answer 1

To determine which gametes can be produced from a plant with the genotype AAPp, we need to consider how the alleles segregate during gamete formation.

1. For the flower position gene (AA):

   • This plant is homozygous with genotype AA, which means it can only contribute the allele A to the gametes.

2. For the flower color gene (Pp):

   • This plant is heterozygous with genotype Pp, which means it can contribute either allele P or allele p to the gametes.

Now, we can combine these possible alleles from each gene to determine the possible gametes:

• From AA (flower position): Only A is contributed.
• From Pp (flower color): Either P or p can be contributed.

Thus, the possible combinations of alleles in the gametes will be:

1. AP (A from flower position, P from flower color)
2. Ap (A from flower position, p from flower color)

The possible gametes from the plant with genotype AAPp are:

• AP
• Ap

The following options are valid gametes for this genotype:

• AP
• Ap

The other options are not possible gametes since:

• Pp: Not a gamete, it's a genotype.
• AA: Not a gamete, it's a full genotype.
• ap: Requires contribution of the recessive alleles (a) from the position gene, which isn't possible as the plant is homozygous AA.

In conclusion, the correct answer is:

• AP
• Ap