To determine if the party can include 10 children and 5 adults within the budget, we can set up an equation based on the information given.
The total cost of the party can be expressed as:
\[ \text{Total Cost} = 150 + 10.50c + 5.50a \]
where:
- \(c\) is the number of children
- \(a\) is the number of adults
Based on the problem, we also need to take into account the budget and set up an inequality:
\[ 150 + 10.50c + 5.50a \leq 300 \]
By plugging the values \(c = 10\) (children) and \(a = 5\) (adults) into the inequality, we can check if it's satisfied:
\[ 150 + 10.50(10) + 5.50(5) \leq 300 \]
Calculating each component:
- \(10.50 \times 10 = 105\)
- \(5.50 \times 5 = 27.50\)
Now plug those values into the inequality:
\[ 150 + 105 + 27.50 \leq 300 \]
Now add the values together:
\[ 150 + 105 = 255 \] \[ 255 + 27.50 = 282.50 \]
So now we have:
\[ 282.50 \leq 300 \]
Since \(282.50\) is less than or equal to \(300\), the inequality holds true.
Thus, it is possible for the party to include 10 children and 5 adults within the budget of $300.