Meg has a solution that is 40% alcohol and another solution that is 60% alcohol. If Meg wants 12 gal of a solution that is 45% alcohol, how much of the two solutions must be mixed?

Answer 1

if she uses x gallons of 40%, then

.40x + .60(12-x) = .45(12)

Answer 2

The answer I got was 9 gal of the 40% alcohol solution and 3 gal of the 60% alcohol solution is needed. Am I right?

Answer 3

Julie bought a card good for 35 visits to a health club and began a workout routine. After y visits, she had y fewer than 35 visits remaining on her card. After 18 visits, how many visits did she have left?

Answer 4

McKenna, you are right.

note that 45% is 1/4 of the way from 40 to 60, so only 1/4 of the total is the higher concentration.

Just sayin' . . .

As for Julie, she had 35-18=17 visits left