May is playing a game with number she decide to rewrite the number 78 using the distributive property which answer they correct way to rewrite 78 using the distributive property of multiplication over addition 78 = 24 + 54 = (6 x 4) + (6 x 9) = 6 (4 x 9) B 78 = 22 + 56 = (2 x 11) + (2 x 28) = 2 (11 + 28) C 78 = 18 + 60 = (6 x 3) + (6 x 10)= 6 (3 + 10)

1 answer

To rewrite the number 78 using the distributive property, we need to express it in the form of \( a \times b + a \times c = a(b + c) \). Let's evaluate the options provided:

A: \( 78 = 24 + 54 = (6 \times 4) + (6 \times 9) = 6(4 + 9) \)

Here, \( 24 + 54 = 78 \), and \( (6 \times 4) + (6 \times 9) = 6(4 + 9) \). This option is correct because it follows the distributive property correctly.

B: \( 78 = 22 + 56 = (2 \times 11) + (2 \times 28) = 2(11 + 28) \)

Here, \( 22 + 56 = 78 \), but \( (2 \times 11) + (2 \times 28) \) equals \( 2(11 + 28) \) incorrectly because \( 11 + 28 = 39\) which, when multiplied by 2, gives 78, but the terms factored out do not properly correspond to the original addition.

C: \( 78 = 18 + 60 = (6 \times 3) + (6 \times 10)= 6(3 + 10) \)

Here, \( 18 + 60 = 78 \), and \( (6 \times 3) + (6 \times 10) = 6(3 + 10) \) is correct as well.

After analyzing all options:

  • A is correct and follows the distributive property accurately.
  • B is incorrect because it doesn't maintain the equivalence under distribution.
  • C is also correct and follows the distributive property accurately.

Therefore, options A and C correctly rewrite the number 78 using the distributive property.