maths:x^4+3x-2/(x^2+1)^3(x-4)=(Ax+B)/(x^2+1)+(Cx+D)/(x^2+1)^2+(Ex+F)/(x^2+1)^3+G/(x-4)+H/(x-4)^2.fine the value of ABCDEFGH,it a partial fraction o plz i need the solution urgently
3 answers
This is DEFINITELY NOT "government"!!
(x^4+3x-2)/((x^2+1)^3(x-4))
=
266 / 4913(x-4)
- 266(x+4) / (x^2+1)
+ 23(x+4) / 289(x^2+1)^2
+ (7-11x) / 17(x^2+1)^3
Problems like this are so tedious that they really test only patience, not knowledge.
=
266 / 4913(x-4)
- 266(x+4) / (x^2+1)
+ 23(x+4) / 289(x^2+1)^2
+ (7-11x) / 17(x^2+1)^3
Problems like this are so tedious that they really test only patience, not knowledge.
and there is no (x-4)^2 term, since your original fraction had none. If you really want that to be included, I can only refer you to
http://www.wolframalpha.com/input/?i=%28x^4%2B3x-2%29%2F%28%28x^2%2B1%29^3%28x-4%29^2%29
Scroll down a bit to the partial fraction breakdown.
http://www.wolframalpha.com/input/?i=%28x^4%2B3x-2%29%2F%28%28x^2%2B1%29^3%28x-4%29^2%29
Scroll down a bit to the partial fraction breakdown.
1 answer