If you are first of all looking for the integral of
v=25sin50πt
it should be
-1/(2π) cos(50πt) + c
the rest is physics, about which I know very little .
from there the mean is usually found by ...
1/(10-0) ( -1/(2π) cos (500π - (-1/2π cos(0) )
= 1/10 (-1/(2π) (1)
= -1/(20π)
I am using "the mean of a function" definition, don't know if it applies to this physics problem.
maths (integ)
voltage v=25sin50πt is applied on a circuit. using integration, find mean and RMS over range t=0 to 10ms .
i got it to 25/2πt^2 cos(2π/9)+c but im not sure that im going the righ way.
1 answer