Math club purchased 3 adult tickets and 12 student tickets for $262.50. Physics club purchased 4 adult tickets and 8 student tickets for $230.00. How much do the adult and student tickets cost?

Answer 1

Nevermind guys, I solved it.
For future strugglers:

equation A: 3a+12s=262.5
equation B: 4a+8s=230

multiply equation B so that a variable can be negated when you add the two equations together. In this case I chose variable (S) so i multiplied equation B by -1.5 so that -3a=-82.5. Solving for a would get a=27.5

Now you just have to plug in a for one of the two original equations and solve for (s).

3(27.5)+12s=262.5
s=15

Answer 2

3x + 12y =262.5 4x + 8y =230
Solve simultaneously x =$24.25 , y =$16.67. . But the question says how much do they cost ansa =4(24.25)=$97 Dat x and y =8(16.67)=$133 this means that child cost =97 and adult cost is $133