We can use the point-slope form of a line or the slope-intercept form to derive the equations based on the provided information. The slope-intercept form of a line is given by the equation:
\[ y = mx + b \]
where \( m \) is the slope and \( b \) is the y-intercept.
Now let's derive the equations based on the information given:
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A line that contains the y-intercept (0, -2) and the slope of -3/4:
- The y-intercept is \( b = -2 \) and the slope \( m = -3/4 \).
- The equation is:
\[ y = -\frac{3}{4}x - 2 \]
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A line that contains the point (0, -8) with a slope of 3/2:
- The y-intercept is \( b = -8 \) and the slope \( m = 3/2 \).
- The equation is:
\[ y = \frac{3}{2}x - 8 \]
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A line that has a slope of 5/3 and a y-intercept of -4:
- Here, the slope \( m = 5/3 \) and the y-intercept \( b = -4 \).
- The equation is:
\[ y = \frac{5}{3}x - 4 \]
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A line that contains the points (0, -2) and (4, 0):
- We can calculate the slope \( m \) using the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - (-2)}{4 - 0} = \frac{2}{4} = \frac{1}{2} \] - Since it passes through (0, -2), we can use the y-intercept \( b = -2 \).
- The equation is:
\[ y = \frac{1}{2}x - 2 \]
- We can calculate the slope \( m \) using the formula:
To summarize the equations:
- \( y = -\frac{3}{4}x - 2 \)
- \( y = \frac{3}{2}x - 8 \)
- \( y = \frac{5}{3}x - 4 \)
- \( y = \frac{1}{2}x - 2 \)