To match the problems with their corresponding simplified radicals, we need to simplify each radical:
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For \( \sqrt{27} \): \[ \sqrt{27} = \sqrt{9 \cdot 3} = \sqrt{9} \cdot \sqrt{3} = 3\sqrt{3} \]
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For \( \sqrt{32} \): \[ \sqrt{32} = \sqrt{16 \cdot 2} = \sqrt{16} \cdot \sqrt{2} = 4\sqrt{2} \]
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For \( \sqrt{75} \): \[ \sqrt{75} = \sqrt{25 \cdot 3} = \sqrt{25} \cdot \sqrt{3} = 5\sqrt{3} \]
Now let's match them:
- \( \sqrt{27} \) matches with \( 3\sqrt{3} \)
- \( \sqrt{32} \) matches with \( 4\sqrt{2} \)
- \( \sqrt{75} \) matches with \( 5\sqrt{3} \)
So the correct matches are:
- \( \sqrt{27} \) -> \( 3\sqrt{3} \)
- \( \sqrt{32} \) -> \( 4\sqrt{2} \)
- \( \sqrt{75} \) -> \( 5\sqrt{3} \)
The final answers are:
- \( \sqrt{27} \) → \( 3\sqrt{3} \)
- \( \sqrt{32} \) → \( 4\sqrt{2} \)
- \( \sqrt{75} \) → \( 5\sqrt{3} \)