Match the following equations to its equivalent below

Y = x^2 - 10x + 16, y = (x+3)^2 - 8, y = (x+9)(x+1), y = x^2 + 2x - 8.
Equivalents: y = x^2 + 6x + 1, y = (x-2)(x-8), y = x^2 + 10x + 9, y = (x + 1)^2 - 9

1 answer

To match the given equations with their equivalents, we'll first rewrite and simplify each of the provided equations and the equivalents where necessary.

  1. For \( Y = x^2 - 10x + 16 \):

    • This can be factored as follows: \[ Y = (x - 2)(x - 8) \] So, it matches with \( y = (x-2)(x-8) \).
  2. For \( y = (x + 3)^2 - 8 \):

    • Expanding the square: \[ y = (x^2 + 6x + 9) - 8 = x^2 + 6x + 1 \] So, it matches with \( y = x^2 + 6x + 1 \).
  3. For \( y = (x + 9)(x + 1) \):

    • Expanding this: \[ y = x^2 + 10x + 9 \] So, it matches with \( y = x^2 + 10x + 9 \).
  4. For \( y = x^2 + 2x - 8 \):

    • This can be rewritten and completed to find the equivalent in vertex form: \[ y = (x + 1)^2 - 9 \] So, it matches with \( y = (x + 1)^2 - 9 \).

Thus, the matches are:

  • \( Y = x^2 - 10x + 16 \) ↔ \( y = (x-2)(x-8) \)
  • \( y = (x + 3)^2 - 8 \) ↔ \( y = x^2 + 6x + 1 \)
  • \( y = (x + 9)(x + 1) \) ↔ \( y = x^2 + 10x + 9 \)
  • \( y = x^2 + 2x - 8 \) ↔ \( y = (x + 1)^2 - 9 \)