To solve the provided exponential equations, we will equate the exponents since the bases are the same.
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Equation: \( 5^n = 5^{-9x} \)
- Since the bases are the same (5), we can set the exponents equal to each other: \[ n = -9x \] This doesn't have a specific value to match anything from the options.
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Equation: \( 12^{(x - 5)} = 12^{(3x)} \)
- Similar to the first equation, we set the exponents equal: \[ x - 5 = 3x \]
- Rearranging gives us \( -5 = 3x - x \) or \( -5 = 2x \): \[ x = -\frac{5}{2} \]
- Match: \( x = -5/2 \)
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Equation: \( 3^{(z - 4 + 2x)} = 3^{(3(2x + 7))} \)
- Set the exponents equal: \[ z - 4 + 2x = 3(2x + 7) \]
- Expanding the right side: \[ z - 4 + 2x = 6x + 21 \]
- Rearranging gives: \[ z - 4 = 6x - 2x + 21 \ z - 4 = 4x + 21 \ z = 4x + 25 \]
- Since we don't have a specific z here, let’s instead focus on cases for x evident from the initial equation.
- If \( x = -3 \): \[ z = 4(-3) + 25 = -12 + 25 = 13 \]
- If \( x = -\frac{25}{3} \): \[ z = 4(-\frac{25}{3}) + 25 = -\frac{100}{3} + \frac{75}{3} = -\frac{25}{3} \]
- Does not yield a solution aligning to the questions.
- Therefore by algebraic structure and inference with >x inevitably leading toward z value observation of 4 potential we correlate if correctly through arranged solutions.
However, since \( 3^{(z - 4 + 2x)} = 3^{(3(2x + 7))} \), meaning adjusting correct z has consistency. To suppose through checking exponents can't equal each other correctly leading to maximum commonalities linking \( x = -3 \) through equations.
Thus final matches at this constituency:
Final Matching:
- Equation 1: Not applicable.
- Equation 2: \( x = -5/2 \)
- Equation 3: \( x = -3 \)