Match the equations to its equivalent in the options:

y = x^2 - 1x - 20

y = (x + 8) (x + 11)

Options:

y = x^2 + 8x + 11

y = x^2 + 19x + 88

1 answer

Let's start by analyzing the first equation given:

  1. Equation to match: \[ y = x^2 - 1x - 20 \]

  2. Factored form: \[ y = (x + 8)(x + 11) \]

Now we will expand the factored form \(y = (x + 8)(x + 11)\):

\[ y = x^2 + 11x + 8x + 88 \] \[ y = x^2 + 19x + 88 \]

Next, we can simplify the original equation \(y = x^2 - 1x - 20\) to confirm if it is equivalent to the expanded terms.

Let's set the right-hand side of the original equation equal to zero and factor it:

To factor \(x^2 - 1x - 20\), we look for two numbers that multiply to \(-20\) (the constant term) and add to \(-1\) (the coefficient of \(x\)). These numbers are \(4\) and \(-5\):

\[ y = (x - 5)(x + 4) \]

However, this does not match with the original factored form \(y = (x + 8)(x + 11)\).

So we can also calculate both polynomial forms.

Comparing both:

The right expanded form of \( (x + 8)(x + 11) = x^2 + 19x + 88 \) matches one of the options.

In summary:

  • The equivalent of \(y = (x + 8)(x + 11)\) is: \[ y = x^2 + 19x + 88 \]

Thus, the match is:

\[ y = x^2 - 1x - 20 \text{ does not match any of the options.} \] \[ y = (x + 8)(x + 11) \text{ matches with } y = x^2 + 19x + 88. \]

So the only matched option is: \[ y = x^2 + 19x + 88 \]