To match the equations with their solutions, we need to solve each equation and determine which one corresponds to which solution.
-
For the equation:
\(3i + 5 = 2i - 7\)
Rearranging gives:
\(3i - 2i = -7 - 5\)
\(i = -12\)
Solution: \(i = -12\) -
For the equation:
\(3(2i - 7) = 15\)
Expanding:
\(6i - 21 = 15\)
Rearranging gives:
\(6i = 15 + 21\)
\(6i = 36\)
\(i = 6\)
Solution: \(i = 6\) -
For the equation:
\(3i + 5 = 3i + 7\)
Rearranging gives:
\(5 = 7\)
This is inconsistent (no solution) -
For the equation:
\(3i + 2i - 7 = 18\)
Simplifying gives:
\(5i - 7 = 18\)
Rearranging gives:
\(5i = 18 + 7\)
\(5i = 25\)
\(i = 5\)
Solution: \(i = 5\) -
For the equation:
\(3(2i + 7) = 6i + 21\)
Expanding:
\(6i + 21 = 6i + 21\)
This is always true (an identity, infinitely many solutions)
Now we can match:
- \(3i + 5 = 2i - 7\) → \(i = -12\)
- \(3(2i - 7) = 15\) → \(i = 6\)
- \(3i + 5 = 3i + 7\) → No solution
- \(3i + 2i - 7 = 18\) → \(i = 5\)
- \(3(2i + 7) = 6i + 21\) → Infinitely many solutions
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