Let's analyze each equation to determine the number of solutions:
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Equation: \(x - 7 = 7 - x\)
- Rearranging gives: \(x + x = 7 + 7\) → \(2x = 14\) → \(x = 7\)
- Number of solutions: One Solution
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Equation: \(3(x + 5) = 3x + 5\)
- Expanding gives: \(3x + 15 = 3x + 5\)
- Rearranging gives: \(15 = 5\), which is false.
- Number of solutions: No Solution
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Equation: \(10 - x = 25\)
- Rearranging gives: \(-x = 25 - 10\) → \(-x = 15\) → \(x = -15\)
- Number of solutions: One Solution
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Equation: \(2(x + 4) = 2x + 5 + 3\)
- Expanding gives: \(2x + 8 = 2x + 8\)
- This is always true for any \(x\).
- Number of solutions: Infinite Solutions
Now, matching the equations with their numbers of solutions:
- \(x - 7 = 7 - x\) → One Solution
- \(3(x + 5) = 3x + 5\) → No Solution
- \(10 - x = 25\) → One Solution
- \(2(x + 4) = 2x + 5 + 3\) → Infinite Solutions
So, summarizing:
- \(x - 7 = 7 - x\) → One Solution
- \(3(x + 5) = 3x + 5\) → No Solution
- \(10 - x = 25\) → One Solution
- \(2(x + 4) = 2x + 5 + 3\) → Infinite Solutions