Match the description of the one variable equation with the number of solutions it will have.

x - 7 = 7 - x ____________
3(x + 5) = 3x + 5 ____________
10 - x = 25 ____________
2(x + 4) = 2x + 5 + 3 _____________
Options: One Solution, Two Solutions, No Solution, Infinite Solutions

3 answers

Let's analyze each equation to determine the number of solutions:

  1. Equation: \(x - 7 = 7 - x\)

    • Rearranging gives: \(x + x = 7 + 7\) → \(2x = 14\) → \(x = 7\)
    • Number of solutions: One Solution
  2. Equation: \(3(x + 5) = 3x + 5\)

    • Expanding gives: \(3x + 15 = 3x + 5\)
    • Rearranging gives: \(15 = 5\), which is false.
    • Number of solutions: No Solution
  3. Equation: \(10 - x = 25\)

    • Rearranging gives: \(-x = 25 - 10\) → \(-x = 15\) → \(x = -15\)
    • Number of solutions: One Solution
  4. Equation: \(2(x + 4) = 2x + 5 + 3\)

    • Expanding gives: \(2x + 8 = 2x + 8\)
    • This is always true for any \(x\).
    • Number of solutions: Infinite Solutions

Now, matching the equations with their numbers of solutions:

  1. \(x - 7 = 7 - x\) → One Solution
  2. \(3(x + 5) = 3x + 5\) → No Solution
  3. \(10 - x = 25\) → One Solution
  4. \(2(x + 4) = 2x + 5 + 3\) → Infinite Solutions

So, summarizing:

  • \(x - 7 = 7 - x\) → One Solution
  • \(3(x + 5) = 3x + 5\) → No Solution
  • \(10 - x = 25\) → One Solution
  • \(2(x + 4) = 2x + 5 + 3\) → Infinite Solutions
are you sure this is correct

Let me double-check the equations and my previous responses for accuracy:

  1. Equation: \(x - 7 = 7 - x\)

    • Rearranging gives: \[ x + x = 7 + 7 \implies 2x = 14 \implies x = 7 \]
    • Number of solutions: One Solution
  2. Equation: \(3(x + 5) = 3x + 5\)

    • Expanding gives: \[ 3x + 15 = 3x + 5 \]
    • Rearranging gives: \[ 15 = 5 \]
    • This is always false.
    • Number of solutions: No Solution
  3. Equation: \(10 - x = 25\)

    • Rearranging gives: \[ -x = 25 - 10 \implies -x = 15 \implies x = -15 \]
    • Number of solutions: One Solution
  4. Equation: \(2(x + 4) = 2x + 5 + 3\)

    • Expanding gives: \[ 2x + 8 = 2x + 8 \]
    • This is always true for any \(x\).
    • Number of solutions: Infinite Solutions

Summary:

  • First equation: \(x - 7 = 7 - x\) → One Solution
  • Second equation: \(3(x + 5) = 3x + 5\) → No Solution
  • Third equation: \(10 - x = 25\) → One Solution
  • Fourth equation: \(2(x + 4) = 2x + 5 + 3\) → Infinite Solutions

Based on the analysis above, the initial conclusion is correct. Thank you for prompting a re-evaluation. If you have further questions or need more explanations, feel free to ask!