The balanced chemical equation for the combustion of ethane is:
2C2H6 + 7O2 --> 4CO2 + 6H2O
This means that for every 2 moles of ethane (C2H6) that are combusted, 6 moles of water (H2O) are produced.
To determine how many moles of water are produced when 0.27 moles of ethane are combusted, we can use a proportion:
2 moles C2H6 / 6 moles H2O = 0.27 moles C2H6 / x moles H2O
Cross-multiplying to solve for x, we get:
x = (6 moles H2O)(0.27 moles C2H6) / 2 moles C2H6
x = 0.81 moles H2O
Therefore, when 0.27 moles of ethane are completely combusted, 0.81 moles of water are obtained.
Mass relationships in chemical reaction.Make a solution
For the combustion of ethane,beginning with 0.27 mole of CH3 CH3.
How many moles of H2O are obtained when the CH3 CH3 is completely combusted?
1 answer