The balanced chemical equation for the combustion of ethane is:
2C2H6 + 7O2 → 4CO2 + 6H2O
This means that for every 2 moles of ethane (CH3CH3) that react, 4 moles of CO2 are produced.
To determine how many moles of CO2 are produced when 0.27 moles of ethane is combusted, we can use a proportion:
2 moles of CH3CH3 : 4 moles of CO2
0.27 moles of CH3CH3 : x moles of CO2
Cross-multiplying and solving for x, we get:
x = (0.27 moles of CH3CH3 x 4 moles of CO2) / 2 moles of CH3CH3
x = 0.54 moles of CO2
Therefore, when 0.27 moles of ethane is completely combusted, 0.54 moles of CO2 are produced.
Mass relationships in chemical reaction.Make a solution
For the combustion of ethane,beginning with 0.27 mole of CH3 CH3.
How many moles of CO2 are obtained when the CH3 CH3 is completely combusted?
1 answer