The balanced equation for the combustion of ethane is:
2CH3CH3 + 7O2 → 4CO2 + 6H2O
This means that for every 2 moles of CH3CH3, we need 7 moles of O2.
Therefore, for 0.27 moles of CH3CH3, we need:
(7 mol O2/2 mol CH3CH3) x 0.27 mol CH3CH3 = 0.945 mol O2
So we need 0.945 moles of O2 to completely consume 0.27 moles of CH3CH3 in the combustion reaction.
Mass relationships in chemical reaction.Make a solution
For the combustion of ethane,beginning with 0.27 mole of CH3 CH3.
How many moles of O2 are required to completely consume the CH3 CH3?
1 answer