The balanced equation tells us that the molar ratio of KOH to KHCO3 is 1:1. This means that for every 1 mole of KOH consumed, 1 mole of KHCO3 is produced.
To determine the amount of KHCO3 produced from 75.9 g of KOH, we need to first convert grams to moles using the molar mass of KOH:
75.9 g KOH x (1 mol KOH / 56.11 g KOH) = 1.35 mol KOH
Since the molar ratio of KOH to KHCO3 is 1:1, we know that 1.35 mol of KHCO3 will be produced.
To convert moles of KHCO3 to grams, we use the molar mass of KHCO3:
1.35 mol KHCO3 x (100.11 g KHCO3 / 1 mol KHCO3) = 135 g KHCO3
Therefore, 75.9 g of KOH will produce 135 g of KHCO3 in this reaction.
Mass relationships in chemical reaction. Make a solution
Consider the reaction
KOH + CO2 -----> KHCO3
How many grams of KOHCO3 are produced from the complete reaction of 75.9 KOH?
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1 answer