Asked by Jobeth
Mass of the Sun = 1.989 x 10^30 kg
Mass of Hydrogen Atom = 1.00794 grams
If we assume the Sun is made totally of hydrogen, how many hydrogen atoms are contained within the Sun? If the Sun converts hald of these hydrogen atoms into helium over its lifetime of about ten billion years, how many hydrogen atoms are converted per second?
Mass of Hydrogen Atom = 1.00794 grams
If we assume the Sun is made totally of hydrogen, how many hydrogen atoms are contained within the Sun? If the Sun converts hald of these hydrogen atoms into helium over its lifetime of about ten billion years, how many hydrogen atoms are converted per second?
Answers
Answered by
Damon
1.989*10^30 /(1.00794*10^-3)
= 1.973 * 10^33
half converted = .9867*10^33 converted
ten billion = 10^10 years
10^10y * 365d/y *24h/d*3600s/h = 3.154*10^17 seconds
so
.9867*10^33 converted/3.154*10^17 seconds
= .3128*10^16
= 3.128 * 10^15
= 1.973 * 10^33
half converted = .9867*10^33 converted
ten billion = 10^10 years
10^10y * 365d/y *24h/d*3600s/h = 3.154*10^17 seconds
so
.9867*10^33 converted/3.154*10^17 seconds
= .3128*10^16
= 3.128 * 10^15
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