mass of 488 mol of calcium carbonate

Answer 1

To find the mass of 488 moles of calcium carbonate, we need to multiply its molar mass by the number of moles.

The molar mass of calcium carbonate (CaCO3) is:

1 atom of calcium = 40.08 g/mol
1 atom of carbon = 12.01 g/mol
3 atoms of oxygen = 3 x 16.00 g/mol = 48.00 g/mol

So, the molar mass of CaCO3 is:

40.08 + 12.01 + 48.00 = 100.09 g/mol

Therefore, the mass of 488 moles of calcium carbonate is:

488 mol x 100.09 g/mol = 48,866.32 g or 48.87 kg (to two decimal places)