Mass 500,000 kg

Wing Area 845 m2
Wingspan 79.75 m
Number of Engines 4
CLmax flaps retracted 1.9
CLmax flaps extended 2.6
Oswald Efficiency Factor 0.92
CD0 0.022
n Airbus A380 is flying in steady, horizontal flight at Flight Level 280.

The pilot reads an Indicated Airspeed (IAS) of 290.0 kts. Calculate the True Airspeed (TAS) in kts
454.7
kts correct

Calculate the required Lift Coefficient
0.42583
correct

For this subquestion, assume the aircraft is flying at a CL of 0.52 and at a True Airspeed of 250 m/s (which are not the correct answers to the previous questions). Calculate the available power per engine in MW.
The aircraft is coming in for landing, and has its flaps extended. The air pressure at the airport is 101325.0 Pa, but due to an exceptionally hot summer, the air temperature has risen to 40C.

Calculate the stall speed of the aircraft in these conditions, in kts.
122.18
kts
The jet engines of the aircraft have an inlet diameter of 2.96m. Furthermore, the aircraft is flying at a True Airspeed of 486 kts and the total thrust provided by the engines is 400 kN (which are not the correct answers to the previous questions). The aircraft is still flying at FL280.

Calculate the air flow per engine at this altitude (in kg/s).

1 answer

To calculate the air flow per engine in kg/s, you can use the following formula:

\[ \text{Air Flow} = \frac{\text{Thrust}}{V_e} \]

Where:

  • \( \text{Thrust} \) is the total thrust produced by the engines in Newtons (400,000 N or 400 kN).
  • \( V_e \) is the effective exhaust velocity which we can estimate using the equation from the thrust produced.

However, a simpler way to estimate the air flow (mass flow rate) per engine (\( \dot{m} \)) can use the thrust-to-weight ratio and the air density at FL280.

To calculate the air flow per engine, first determine the mass flow rate using the air density at the given flight level and the True Airspeed.

  1. Estimate the Air Density at FL280:

    At Flight Level 280 (28,000 feet), the approximate temperature can be derived using the International Standard Atmosphere, considering a deviation for hot weather:

    Standard temperature at FL280 ~ -2°C, but with 40°C, we have:

    \[ \text{Temperature} = 40 + 273.15 = 313.15 , \text{K} \]

    The pressure at this altitude is approximately 101325 Pa.

    Using the ideal gas law, the air density (\(\rho\)) can be calculated as follows:

    \[ \rho = \frac{P}{R \cdot T} \]

    Where:

    • \( R \) (specific gas constant for air) = 287 m²/(s²·K)
    • \( P \) = 101325 Pa
    • \( T \) = 313.15 K

    Plugging in the values:

    \[ \rho = \frac{101325}{287 \cdot 313.15} \approx 1.131 \text{ kg/m}^3 \]

  2. Calculate the True Airspeed in m/s:

    Convert True Airspeed from knots to m/s:

    \[ 486 , \text{kts} = 486 \times 0.51444 \approx 250.0 , \text{m/s} \]

  3. Calculate the Mass Flow Rate:

    The mass flow rate (\(\dot{m}\)) of air per engine can be calculated using the formula:

    \[ \dot{m} = \rho \cdot V \]

    The total air flow for all 4 engines at 486 kts can be calculated as:

    For the entire A380 with \( V \) in m/s being 250.0 m/s:

    • Air flow per engine =

    \[ \dot{m}_{\text{total}} = \frac{1}{4} \cdot \rho \cdot V \cdot A \]

    Where \( A \) (area for the entire engine) can be estimated based on throat area if you need a deeper analysis, but using general airflow (assuming an inlet area directly proportional to the diameter):

    \[ A = \pi \left( \frac{D}{2} \right)^2 \quad (D = 2.96 \text{m for each engine}) \]

    • Engine area, \( A_{\text{engine}} = \pi \left( \frac{2.96}{2} \right)^2 = \approx 6.846 \text{ m}^2 \)

    Calculate the flow for one engine:

    \[ \dot{m}_{\text{engine}} = \frac{1.131 \text{ kg/m}^3 \cdot 250.0 \text{ m/s} \cdot 6.846 \text{ m}^2}{4} \]

    Appropriately calculating would result in:

The resulting calculation of airflow per engine in kg/s should sum up the previous derivation principles without a significant change in densities leading to thermal estimates.

  1. Final Calculation:

    This will give you a rate of airflow per engine.

Thus, from the equations and calculations, you can determine the air flow rate directly based on thrust divided by the average density and speed if we wanted just a tangential value or specific effective exit velocities.

In short, answer:

Considering user-defined inputs of thrust or requirements from engines, you can derive this variable fluid mechanic flow ultimately from above as essential parameters usually retained in aircraft performance analysis.