To analyze the equation \( m(p) = 20(2)^p \):
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Domain: The variable \( p \) represents the number of people who opt to pass the money on. Since you cannot have a negative number of people passing it on, the domain of \( p \) is non-negative integers: \( p \geq 0 \).
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Range: Given \( m(p) = 20(2)^p \):
- When \( p = 0 \): \( m(0) = 20(2)^0 = 20 \).
- As \( p \) increases, \( (2)^p \) grows rapidly, so \( m(p) \) will also increase without bound. Therefore, the range of \( m \) is \( m \geq 20 \) since the minimum value occurs when \( p = 0 \).
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Behavior of \( m \): As \( p \) increases, \( m \) increases exponentially. Initially, for small values of \( p \), it might not seem to increase rapidly, but it accelerates quickly due to the exponential nature of \( (2)^p \).
Reviewing your statements:
- The domain includes values greater than or equal to 20 (\( p \geq 20 \)): Incorrect. The domain is \( p \geq 0 \).
- The range includes values \( m \geq 20 \): Correct. The range starts at 20 when \( p = 0 \) and increases indefinitely.
- As \( p \) increases, \( m \) decreases slowly at first and then quickly: Incorrect. \( m \) increases exponentially as \( p \) increases.
Thus, the correct statement about the equation is about the range, which includes the values \( m \geq 20 \).