To analyze the function \( m(p) = 20(2)^p \) where \( m \) represents the money and \( p \) represents the number of people who opt to pass it on, we can determine the following:
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Range of the function:
- The equation \( m(p) = 20(2)^p \) outputs values for money starting from \( m(0) = 20(2)^0 = 20 \). As \( p \) increases (meaning more people choose to pass it on), \( m \) grows exponentially without bound. Therefore, the range of \( m \) is \( m \geq 20 \).
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Domain of the function:
- The variable \( p \), representing the number of people passing on the money, can be any non-negative integer (0, 1, 2, ...). Thus, the domain is \( p \geq 0 \).
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Behavior of the function as \( p \) increases:
- As \( p \) increases, \( m \) increases quickly because every time \( p \) increases by 1, \( m \) is multiplied by 2. Thus, \( m \) grows rapidly, which means \( m \) increases quickly at first and then keeps increasing faster.
Based on these analyses, we can evaluate the statements provided:
- The range (m-values) includes the values \( m \geq 20 \). This is true.
- The domain (p-values) include the values greater than or equal to 20 (p ≥ 20). This is false; the domain is \( p \geq 0 \), not starting at 20.
- As p increases, m decreases slowly at first and then quickly. This is false; \( m \) does not decrease; it increases.
- As p increases, m increases quickly at first and then slowly. This is misleading because \( m \) does not increase slowly at first; it increases quickly and continues to increase quickly.
In conclusion, the true statement is:
- The range (m-values) includes the values \( m \geq 20 \).