To analyze the function \( m(p) = 20(2)^p \):
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Behavior of m(p):
- As \( p \) increases, \( (2)^p \) grows exponentially. This means that \( m(p) \) increases very quickly as \( p \) increases. So the statement about m increasing quickly at first and then slowly is incorrect.
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Domain of p:
- \( p \) represents the number of people who opt to pass the money on, so it must be a non-negative integer. Therefore, the correct domain is \( p \geq 0 \) (not \( p \geq 20 \)).
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Range of m:
- The minimum value of \( m \) occurs when \( p = 0 \): \( m(0) = 20(2)^0 = 20 \). As \( p \) increases, \( m(p) \) can take on any value greater than 20. Thus, the range is \( m \geq 20 \).
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Behavior of m in relation to decreasing:
- The statement about \( m \) decreasing is false because \( m(p) \) increases as \( p \) increases.
Bringing this all together:
- The correct statement regarding the equation is: The range (m-values) includes the values (m ≥ 20).