Let's analyze the given equation \( m(p) = 20(2)^p \).
-
As \( p \) increases, \( m \) increases quickly at first and then slowly: This is false. The function \( m(p) = 20(2)^p \) is an exponential function, which means it increases rapidly as \( p \) increases. There is no "slow" increase; instead, it increases increasingly more rapid.
-
The range (m-values) includes the values \( m \geq 20 \): This is true. When \( p = 0 \), \( m(0) = 20(2)^0 = 20 \). As \( p \) increases, \( m \) will only get larger because \( 2^p \) grows exponentially. Thus, all values of \( m \) will be greater than or equal to 20.
-
As \( p \) increases, \( m \) decreases slowly at first and then quickly: This is false. The function does not decrease; it increases as \( p \) increases.
-
The domain (p-values) include the values greater than or equal to 20 (p ≥ 20): This is false. The domain of \( p \) is all real numbers (typically non-negative integers in practical scenarios for this type of problem), but does not start at 20. It can be \( p = 0, 1, 2, ...\) and so on.
Conclusion:
The correct statement among the options is: The range (m-values) includes the values \( m \geq 20 \).