Mary wants to throw a can straight up into the air and then hit it with a second can. She wants the collision to occur at height h=5.0 m above the throw point. In addition, s/he knows that she needs t1=3.0 s between successive throws. Assuming that s/he throws both cans with the same speed. Take g to be 9.81 m/s2.

Question

hint: you might want to look at Professor's Lewin's Help Session before you attempt this problem.

(a) How long it takes (in s) after the first can has been thrown into the air for the two cans to collide?

Δt=

(b) Find the initial speed of the cans (in m/s).

v0=

Answer 1

4.981

Answer 2

Please help with this question!!

Answer 3

trfhyd