To solve the quadratic equation \(3x^2 + 2x - 8 = 0\), Martin likely factored it by grouping.
The equation can be grouped as follows:
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First, we can rearrange it: \(3x^2 + 2x - 8 = 0\).
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The terms can be grouped based on a common factor. Notice that the quadratic can be expressed in a way to facilitate factoring. We can look for two pairs:
Consider the first line: \(3x^2 + 6x - 4x - 8\) which can be grouped in pairs: \( (3x^2 + 6x) + (-4x - 8) \)
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Now, factor out the GCF from each pair: \(3x(x + 2) - 4(x + 2) = 0\)
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At this point, notice that both terms contain \((x + 2)\), thus you can factor that out: \((3x - 4)(x + 2) = 0\)
Now that we have reviewed the factoring steps, looking at your options, the missing step where Martin divided or factored out the greatest common factor is:
Option: \(3x(x + 2) - 4(x + 2) = 0\)
This is the correct step showing the necessary factoring before proceeding to the next step of solving the equation.