Martin is making a candy that contains 90% milk chocolate and the rest caramels. The candy has 3 pounds of caramels.

Question

Part A: Write an equation using one variable that can be used to find the total number of pounds of milk chocolate and caramels in the candy. Define the variable used in the equation.

Part B: How many pounds of milk chocolate are present in the candy? Show your work.
Is this right?: Total amount of chocolate will be p.
The amount of caramel=3 pounds;
The amount of milk=90%=0.9/0.1*3=27 pounds milk
Therefore the total amount of milk in candy will be:
m=0.9p
The total amount of caramel will be:
c=0.9p

Percentage of Caramel in chocolate is 10%. The amount of milk will therefore be:
0.9/0.1*3=27  pounds

Answer 1

Please help me!

Answer 2

Could someone verify my answer please?

Answer 3

27 pounds is right.

Answer 4

The rest isn't right?

Answer 5

Let the total amount of candy be x lbs

So .9x is milk chocolate
and .1x is caramel

but .1x = 3
x = 3/.1 = 30 lbs

So the total amount of candy is 30 lbs, with
90% of 30 or 27 lbs of chocolate, and
10% of 30 or 3 lbs of caramel

The question said to use one variable, I see you used m, p, and c .