To determine the vertex of the quadratic function f(x) = x^2 - x + 2, we first need to find the x-coordinate of the vertex.
The x-coordinate of the vertex of a quadratic function in the form f(x) = ax^2 + bx + c is given by x = -b/2a.
In this case, a = 1, and b = -1. Plugging these values into the formula, we get x = -(-1) / 2*1 = 1/2.
Now, plug in the x-coordinate into the original function to find the y-coordinate of the vertex:
f(1/2) = (1/2)^2 - 1/2 + 2 = 1/4 - 1/2 + 2 = 1/4 - 2/4 + 8/4 = 7/4
Therefore, the vertex of the function f(x) = x^2 - x + 2 is at (1/2, 7/4).
Marsha wants to determine the vertex of the quadratic function f(x) = x2 – x + 2. What is the function’s vertex?
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