Let's assume the number of people they invite is x.
The cost of the reception hall is $560 + $32x.
According to the budget, $560 + $32x ≤ $5000.
We can subtract $560 from both sides of the inequality to get $32x ≤ $5000 - $560, which simplifies to $32x ≤ $4440.
To solve for x, we divide both sides of the inequality by $32: x ≤ $4440 / $32.
x ≤ 138.75.
The greatest number of people they may invite and still stay within their budget is 138 people.
Mark and Heather Starr are celebrating their 25th anniversary by having a reception at a local reception hall. They have budgeted $5,000 for their reception. If the reception hall charges a 560 cleanup lee plus $32 per person find the greatest number of people that they may invite and still stay within their budget
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