To determine which substance is most likely Marjorie's unknown, we must consider the properties provided for each substance in relation to the information Marjorie has:
- Density: The unknown substance has a density of about 2.2 g/mL.
- Solubility in water: The behavior with water doesn't directly affect our choice based on the provided information.
- Solubility in CCl4: The unknown is insoluble in CCl4.
Now let's evaluate each of the given substances:
A. NaCl
- Density: 2.165 g/mL
- Solubility in CCl4: insoluble
B. SiO2
- Density: 2.634 g/mL
- Solubility in CCl4: insoluble
C. C10H8 (naphthalene)
- Density: 1.14 g/mL
- Solubility in CCl4: soluble
D. FeCl3
- Density: 2.898 g/mL
- Solubility in CCl4: insoluble
Now, based on density alone:
- NaCl has a density close to the unknown (2.165 g/mL).
- SiO2 has a higher density than the unknown (2.634 g/mL).
- C10H8 has a significantly lower density (1.14 g/mL).
- FeCl3 has a higher density (2.898 g/mL).
Considering solubility in CCl4, NaCl and SiO2 are both insoluble, whereas C10H8 is soluble, and FeCl3 is insoluble, but has a density too high.
Based on compatibility of both density and solubility, NaCl (Density: 2.165 g/mL, Insoluble in CCl4) is the closest match.
Thus, the most likely identity of Marjorie's unknown substance is:
A. NaCl.