Marit and jennifer had an equal number of crackers. Each day, Marit ate 12 crackers and Jennifer ate 6 more crackers than Marit. When Jennifer had 24 crackers left, Marit had 96 crackers left. How many crackers did each of them have at first?

3 answers

Marit ate 12 crackers/day.
Jennifer ate 12+6 = 18 crackers/day.

Difference = 96-24 = 72 crackers

72Crackers/6Crackers/day = 12 Days

Marit=12crackers/day * 12Days=144 Crackers.

Jennifer=18crackers/day*12days=216 crackers.
after n days:
M - 12n = 96
J - 18n = 24

Given M = J; they had same number of crackers

so M - 12n = 96
-M + 18n = -24

so 6n = 72 that is n = 12

M - 12 x 12 = 96
M = 240

J - 18 x 12 = 24
J - 216 = 24
J = 240

Answer: 240 both had 240 crackers to begin with.
so confusing