v(south) =12.9cos23 -6.6 =5.27 m/s
v(west) =12.9sin23=5.04 m/s
v=sqrt{v(west)²+v(south)²} =
=sqrt{5.04²+5.27²} =7.3 m/s
tanα =5.04/5.27 =0.95
α=43.7º
Mario, a hockey player, is skating due south at a speed of 6.6 m/s relative to the ice. A teammate passes the puck to him. The puck has a speed of 12.9 m/s and is moving in a direction of 23° west of south, relative to the ice. What are the magnitude and direction (relative to due south) of the puck's velocity, as observed by Mario?
3 answers
Why was the 6.6 subtracted because it's in the same direction as the 12.9cos23 vector?
Why are the south velocities subtracted because they are in the same direction?