Maria Prytz is playing curling and is gonna toss away the rock along the ice so it stops at the house. The house is 31 m away from where she tosses the rock. The friction force is 1.6 N and the rock weighs 19.5 kg. At which speed should Maria toss the rock?

Answer 1

First, we need to calculate the force of gravity acting on the rock:

Force of gravity = mass x gravitational acceleration
Force of gravity = 19.5 kg x 9.81 m/s^2
Force of gravity = 191.295 N

Next, we need to calculate the net force acting on the rock:

Net force = force of gravity - friction force
Net force = 191.295 N - 1.6 N
Net force = 189.695 N

Now, we can use the equation for force to calculate the acceleration of the rock:

Net force = mass x acceleration
189.695 N = 19.5 kg x acceleration
Acceleration = 189.695 N / 19.5 kg
Acceleration = 9.73 m/s^2

Finally, we can use the equation for acceleration to calculate the speed Maria should toss the rock:

Acceleration = (final velocity^2 - initial velocity^2) / (2 x distance)
9.73 m/s^2 = (0 - initial velocity^2) / (2 x 31 m)
Initial velocity = sqrt(2 x 9.73 m/s^2 x 31 m)
Initial velocity = sqrt(601.18)
Initial velocity ≈ 24.52 m/s

Therefore, Maria should toss the rock at a speed of approximately 24.52 m/s.

Answer 2

u sure

Answer 3

Let's reevaluate the calculations:

First, calculate the force of gravity:

Force of gravity = mass x gravitational acceleration
Force of gravity = 19.5 kg x 9.81 m/s^2
Force of gravity = 191.295 N

Calculate the net force acting on the rock:

Net force = force of gravity - friction force
Net force = 191.295 N - 1.6 N
Net force = 189.695 N

Calculate the acceleration of the rock:

Net force = mass x acceleration
189.695 N = 19.5 kg x acceleration
Acceleration = 189.695 N / 19.5 kg
Acceleration = 9.73 m/s^2

Calculate the speed Maria should toss the rock:

v_f^2 = v_i^2 + 2as
0 = v_i^2 + 2(-9.73 m/s^2)(31 m)
v_i^2 = 2(9.73 m/s^2)(31 m)
v_i^2 = 602.06
v_i ≈ 24.54 m/s

Therefore, Maria should toss the rock at a speed of approximately 24.54 m/s. Thank you for pointing out the discrepancy, and I hope this calculation is clearer.