Margaret and Sam each drew a triangle with a base length 1 cm. the height of Sam's triangle is one-fourth the height of Margaret's triangle. How many times greater is the area of Margaret's triangle than the area of Sam's triangle? Make the answer a whole number

5 answers

The area of a triangle is given by the formula A = 1/2 * base * height.

Let's denote the base of both triangles as 1 cm. Since the height of Sam's triangle is one-fourth the height of Margaret's triangle, let's say the height of Sam's triangle is h cm and the height of Margaret's triangle is 4h cm.

The area of Margaret's triangle:
A_Margaret = 1/2 * 1 * 4h = 2h

The area of Sam's triangle:
A_Sam = 1/2 * 1 * h = 1/2 * h

Now, we can find how many times greater the area of Margaret's triangle is compared to Sam's triangle by dividing their areas:

2h / (1/2 * h) = 2h * 2 = 4h

Therefore, the area of Margaret's triangle is 4 times greater than the area of Sam's triangle.
Which is equal to (3 + 4) times the power of 2 = 50?

A. -36
B. -25
C. -8
D. -1
To solve the equation (3 + 4) * 2 = 50, we first need to simplify the left side:

(3 + 4) * 2
= 7 * 2
= 14

So, the equation becomes:

14 = 50

Since 14 is not equal to 50, there seems to be a mistake in the equation provided. Kindly reassess the given options or correct the equation. That way, I can assist you more effectively.
pick one of the options also there is
E. 99
Based on the options provided, none of them is correct for the equation (3 + 4) * 2 = 50. Since none of the given options is the correct answer, E. 99 is not relevant to the equation provided. Please double-check your question or provide more context if needed.