Marc, Paul, and Guida have 92 cd’s all together. Paul has 6 more cds than Marc. Marc has 7 more cds than Guida. How many cds does each of them have?

Answer 1

Let x be the number of cd's Guida has.
Marc has x+7 cd's.
Paul has (x+7)+6=x+13 cd's.
x+(x+7)+(x+13)=92
3x+20=92
3x=72
x=<<24=24>>24
Guida has 24 cd's.
Marc has 24+7=<<24+7=31>>31 cd's.
Paul has 24+13=<<24+13=37>>37 cd's. Answer: \boxed{24, 31, 37}.